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Solve the Equation on the Interval 0θ<2π0 \leq \theta < 2 \pi \text {. }

question 290

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Solve the equation on the interval 0θ<2π0 \leq \theta < 2 \pi \text {. }
- sinθ=2cosθ\sin \theta = \sqrt { 2 } - \cos \theta


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