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Solve the Problem tt (In Seconds) Required for a Block to Slide Down an (In

question 156

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Solve the problem.
-If friction is ignored, the time tt (in seconds) required for a block to slide down an inclined plane is given by the fc
t=2agsinθcosθt = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }
where aa is the length (in feet) of the base and g32g \approx 32 feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base a=12\mathrm { a } = 12 when θ=58\theta = 58 ^ { \circ } ? If necessary, round the answer to the nearest tenth of a second. mula


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