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Solve the Problem S=kd3sin2θcosθ\mathrm { S } = \mathrm { kd } ^ { 3 } \sin ^ { 2 } \theta \cos \theta

question 96

Short Answer

Solve the problem.
-The strength S of a wooden beam with rectangular cross section is given by the formula S=kd3sin2θcosθ\mathrm { S } = \mathrm { kd } ^ { 3 } \sin ^ { 2 } \theta \cos \theta where d is the diagonal length, θ\theta the angle illustrated, and k is a constant that varies with the type of wood used.  Solve the problem. -The strength S of a wooden beam with rectangular cross section is given by the formula  \mathrm { S } = \mathrm { kd } ^ { 3 } \sin ^ { 2 } \theta \cos \theta  where d is the diagonal length,  \theta  the angle illustrated, and k is a constant that varies with the type of wood used.   Let  \mathrm { d } = 1  and express the strength  \mathrm { S }  in terms of the constant  \mathrm { k }  for  \theta = 45 ^ { \circ } , 50 ^ { \circ } , 55 ^ { \circ } , 60 ^ { \circ } , and  65 ^ { \circ } . Does the strength always increase as  \theta  gets larger? Let d=1\mathrm { d } = 1 and express the strength S\mathrm { S } in terms of the constant k\mathrm { k } for θ=45,50,55,60\theta = 45 ^ { \circ } , 50 ^ { \circ } , 55 ^ { \circ } , 60 ^ { \circ } , and 6565 ^ { \circ } . Does the strength always increase as θ\theta gets larger?


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