Solve the Problem $$t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$$

question 112

Multiple Choice

Solve the problem.
-If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the formula $$t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$$
where $a$ is the length (in feet) of the base and $g \approx 32$ feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base $a = 14$ when $\theta = 45 ^ { \circ }$ ? If necessary, round the answer to the nearest tenth of a second.

• A) \(1.3 \mathrm { sec }\)
• B) \(0.3 \mathrm { sec }\)
• C) \(1.4 \mathrm { sec }\)
• D) \(1.1 \mathrm { sec }\)

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