Examlex

Solved

Solve the Problem h(x)=32x2(270)2+x+300h ( x ) = \frac { - 32 x ^ { 2 } } { ( 270 ) ^ { 2 } } + x + 300

question 101

Multiple Choice

Solve the problem.
-A projectile is fired from a cliff 300 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 270 feet per second. The height h of the projectile above the water is given by h(x) =32x2(270) 2+x+300h ( x ) = \frac { - 32 x ^ { 2 } } { ( 270 ) ^ { 2 } } + x + 300 ,
Where x is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the
Projectile.


Definitions:

Related Questions