An Arithmetic Sequence Is Given $$\left\{ \frac { 1 } { 3 } + \frac { n } { 8 } \right\}$$

question 230

Multiple Choice

An arithmetic sequence is given. Find the common difference and write out the first four terms.
- $$\left\{ \frac { 1 } { 3 } + \frac { n } { 8 } \right\}$$

• A) \(\mathrm { d } = \frac { 1 } { 3 } ; \frac { 11 } { 24 } , \frac { 7 } { 12 } , \frac { 17 } { 24 } , \frac { 5 } { 6 }\)
• B) \(\mathrm { d } = \frac { 1 } { 3 } ; \frac { 1 } { 3 } , \frac { 11 } { 24 } , \frac { 7 } { 12 } , \frac { 17 } { 24 }\)
• C) \(\mathrm { d } = \frac { 1 } { 8 } ; \frac { 11 } { 24 } , \frac { 7 } { 12 } , \frac { 17 } { 24 } , \frac { 5 } { 6 }\)
• D) \(\mathrm { d } = \frac { 1 } { 8 } ; \frac { 1 } { 3 } , \frac { 11 } { 24 } , \frac { 7 } { 12 } , \frac { 17 } { 24 }\)

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Definitions:

Chromosomes Decondense

A process where chromosomes relax from their highly structured and compact form to a less condensed, more accessible state, typically occurring at the end of mitosis or meiosis.

Telophase

The final phase of cell division, during which the chromosomes de-condense, nuclear envelopes re-form around the divided chromosomes, completing cytokinesis.

Chromatin Condenses

The process where chromatin fibers coil and fold to form more compact structures, typically during cell division.

Prophase

The first stage of cell division in both mitosis and meiosis, during which the chromatin condenses into visible chromosomes, and the nuclear envelope begins to disintegrate.