Solve the System Using the Inverse Method$$\left\{ \begin{aligned}
x + 2 y + 3 z & = - 8 \
x + y + z & = - 4 \
- x + y + 2 z & = - 1
\end{aligned} \right.$$

Question

Examlex · Accepted Answer

The Answer of Solve the System Using the Inverse Method$$\left\{ \begin{aligned}
x + 2 y + 3 z & = - 8 \
x + y + z & = - 4 \
- x + y + 2 z & = - 1
\end{aligned} \right.$$

Solve the System Using the Inverse Method $\left\{ \begin{aligned}x + 2 y + 3 z & = - 8 \\x + y + z & = - 4 \\- x + y + 2 z & = - 1\end{aligned} \right.$

Definitions:

Solve the System Using the Inverse Method {x+2y+3z=−8x+y+z=−4−x+y+2z=−1\left\{ \begin{aligned}x + 2 y + 3 z & = - 8 \\x + y + z & = - 4 \\- x + y + 2 z & = - 1\end{aligned} \right.⎩⎨⎧​x+2y+3zx+y+z−x+y+2z​=−8=−4=−1​

Definitions:

Solve the System Using the Inverse Method $\left\{ \begin{aligned}x + 2 y + 3 z & = - 8 \\x + y + z & = - 4 \\- x + y + 2 z & = - 1\end{aligned} \right.$