Solve the System for X and Y Using Cramerʹs Rule $$\begin{array} { l } \frac { 1 } { a } x + \frac { 1 } { b } y = a b \\x + y = a\end{array}$$

question 285

Multiple Choice

Solve the system for x and y using Cramerʹs rule. Assume a and b are nonzero constants.
- $$\begin{array} { l } \frac { 1 } { a } x + \frac { 1 } { b } y = a b \\x + y = a\end{array}$$

• A) \(\left. \left\{ \frac { a ( b - a ) \left( b ^ { 2 } - 1 \right) } { a b ^ { 2 } } , \frac { ( b - a ) ( 1 - a b ) } { a b } \right) \right\}\)
• B) \(\left\{ \left( a b ( 1 - a b ) , a ^ { 2 } \left( b ^ { 2 } - 1 \right) \right) \right\}\)
• C) \(\left\{ \left( \frac { a ^ { 2 } \left( b ^ { 2 } - 1 \right) } { b - a } , \frac { a b ( 1 - a b ) } { b - a } \right) \right\}\)
• D) \(\left\{ \left( \frac { a ^ { 2 } b \left( b ^ { 2 } - 1 \right) } { b - a } , \frac { a b ( 1 - a b ) } { b - a } \right) \right\}\)

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