Solve the Equation for Solutions in the Interval [0, 2 $$\sin x \cos x = \frac { 1 } { 2 }$$

question 484

Multiple Choice

Solve the equation for solutions in the interval [0, 2 π) .
- $$\sin x \cos x = \frac { 1 } { 2 }$$

• A) \(\left\{ \frac { \pi } { 4 } , \frac { 5 \pi } { 4 } \right\}\)
• B) \(\left\{ \frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } \right\}\)
• C) \(\{ 0 \}\)
• D) \(\left\{ 0 , \frac { \pi } { 4 } , \pi , \frac { 5 \pi } { 4 } \right\}\)

Apply the method of difference to identify causal relationships.

Analyze the role of disconfirming evidence in strengthening generalizations.

Understand how the method of concomitant variations contributes to identifying causal relations.

Apply the method of residues to infer additional causal factors in complex scenarios.

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