Solve the Problem $d$ From a Long Wall $d$ Is Given By $\mathrm { d } = 3 \tan 2 \pi \mathrm { t }$

question 76

Multiple Choice

Solve the problem.
-A rotating beacon is located a distance $d$ from a long wall. The distance $d$ is given by $\mathrm { d } = 3 \tan 2 \pi \mathrm { t }$ ,
where $t$ is the time measured in seconds since the beacon started rotating. Solve the equation for $\mathrm { t }$ .

• A) \(\mathrm { t } = \frac { 1 } { 2 \pi } \tan \frac { \mathrm { d } } { 3 }\)
• B) \(t = 2 \pi \arctan \frac { \mathrm { d } } { 3 }\)
• C) \(t = \frac { 1 } { 2 \pi } \arctan \frac { d } { 3 }\)
• D) \(t = 2 \pi \tan \frac { d } { 3 }\)

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