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Determine All Solutions of the Equation in Radians sinθ2\sin \frac { \theta } { 2 }

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Determine all solutions of the equation in radians.
-Find sinθ2\sin \frac { \theta } { 2 } , given that sinθ=35\sin \theta = - \frac { 3 } { 5 } and θ\theta terminates in 270<θ<360270 ^ { \circ } < \theta < 360 ^ { \circ } .


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