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Give the Degree Measure of θ θ=arctan(33)\theta = \arctan \left( \frac { \sqrt { 3 } } { 3 } \right)

question 193

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Give the degree measure of θ.
- θ=arctan(33) \theta = \arctan \left( \frac { \sqrt { 3 } } { 3 } \right)

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