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Solve the Equation for Exact Solutions Over the Interval [0 sin2xcos2x=0\sin ^ { 2 } x - \cos ^ { 2 } x = 0

question 194

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Solve the equation for exact solutions over the interval [0, 2π) .
- sin2xcos2x=0\sin ^ { 2 } x - \cos ^ { 2 } x = 0

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