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Solve the Equation for Solutions in the Interval [0°, 360°) sin2θ=12\sin 2 \theta = - \frac { 1 } { 2 }

question 449

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Solve the equation for solutions in the interval [0°, 360°) . Round to the nearest degree.
- sin2θ=12\sin 2 \theta = - \frac { 1 } { 2 }


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