Solve the Problem $= 11 \pi \mathrm { sec }$ , Frequency

question 127

Multiple Choice

Solve the problem.
-Determine the period and frequency of oscillation when a pendulum of length 11 feet is released after being displaced 2 radians. Round constants to 8 decimal places, if necessary.

• A) Period \(= 11 \pi \mathrm { sec }\), frequency \(= \frac { 1 } { 11 \pi }\) cycles per sec
• B) Period \(= 2 \pi \sqrt { 2.90909091 }\) sec, frequency \(= \frac { 1 } { 2 \pi } \sqrt { 0.34375 }\) cycles per sec
• C) Period \(= 2 \pi \sqrt { 0.34375 }\) sec, frequency \(= \frac { 1 } { 2 \pi } \sqrt { 2.90909091 }\) cycles per sec
• D) Period \(= \frac { \pi } { 11 }\) sec, frequency \(= \frac { 11 } { \pi }\) cycles per sec

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