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Use the Summation Properties to Evaluate the Series - i=164i\sum _ { i = 1 } ^ { 6 } 4 i

question 52

Multiple Choice

Use the summation properties to evaluate the series. The following rules may be needed: nnni=n(n+1) 2;i2=n(n+1) (2n+1) 6;i3=n2(n+1) 24i=1i=1i=1\begin{array} { l l l } \mathrm { n } & \mathrm { n } & \mathrm { n } \\\sum \mathrm { i } = \frac { \mathrm { n } ( \mathrm { n } + 1 ) } { 2 } ; & \sum \mathrm { i } ^ { 2 } = \frac { \mathrm { n } ( \mathrm { n } + 1 ) ( 2 \mathrm { n } + 1 ) } { 6 } ; & \sum \mathrm { i } ^ { 3 } = \frac { \mathrm { n } ^ { 2 } ( \mathrm { n } + 1 ) ^ { 2 } } { 4 } \\\mathrm { i } = 1 & \mathrm { i } = 1 & \mathrm { i } = 1\end{array}
- i=164i\sum _ { i = 1 } ^ { 6 } 4 i


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