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Decide What Values of the Variable Cannot Possibly Be Solutions xx3+11x9x+9=0\frac { x } { x - 3 } + \frac { 11 x } { 9 x + 9 } = 0

question 334

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- xx3+11x9x+9=0\frac { x } { x - 3 } + \frac { 11 x } { 9 x + 9 } = 0


Definitions:

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