Solve the Problem $\mathrm { D } = \sqrt { \mathrm { L } ^ { 2 } + \mathrm { W } ^ { 2 } + \mathrm { H } ^ { 2 } }$

question 138

Multiple Choice

Solve the problem.
-The length of the diagonal of a box is given by $\mathrm { D } = \sqrt { \mathrm { L } ^ { 2 } + \mathrm { W } ^ { 2 } + \mathrm { H } ^ { 2 } }$ where $\mathrm { L } , \mathrm { W }$ , and $\mathrm { H }$ are the length, width, and height of the box. Find the length of the diagonal, D, of a box that is $4 \mathrm { ft }$ long, $3 \mathrm { ft }$ high, and $2 \mathrm { ft }$ wide. Give the exact value.

• A) \(9 \mathrm { ft }\)
• B) \(2 \sqrt { 6 } \mathrm { ft }\)
• C) \(\sqrt { 29 } \mathrm { ft }\)
• D) \(24 \mathrm { ft }\)