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A Discrete Random Variable X Can Assume Five Possible Values

question 47

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A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the probability for the value of x = 5. x235810p(x) 0.100.20???0.300.10\begin{array} { c | c c c c c } \mathrm { x } & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm { p } ( \mathrm { x } ) & 0.10 & 0.20 & ? ? ? & 0.30 & 0.10\end{array}


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