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A Discrete Random Variable X Can Assume Five Possible Values x235810p(x)0.100.200.300.300.10\begin{array}{c|ccccc}\mathrm{x} & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}

question 127

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A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the mean of the distribution. x235810p(x) 0.100.200.300.300.10\begin{array}{c|ccccc}\mathrm{x} & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}


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