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-A Ball Is Thrown Upward with an Initial Velocity h=4.9t2+21t+110h = - 4.9 t ^ { 2 } + 21 t + 110

question 172

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-A ball is thrown upward with an initial velocity of 21 meters per second from a cliff that is 70 meters high. The height of the ball is given by the quadratic equation h=4.9t2+21t+110h = - 4.9 t ^ { 2 } + 21 t + 110 where h\mathrm { h } is in meters and t\mathrm { t } is the time in seconds since the ball was thrown. Find the time that the ball will be 40 meters from the ground. Round your answer to the nearest tenth of a second.


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