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-A Rocket Is Launched from the Top of a Cliff

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-A rocket is launched from the top of a cliff that is 80 feet high with an initial velocity of 80 feet per second. The height, h(t) \mathrm { h } ( \mathrm { t } ) , of the rocket after t\mathrm { t } seconds is given by the equation h(t) =16t2+80t+80\mathrm { h } ( \mathrm { t } ) = - 16 \mathrm { t } ^ { 2 } + 80 \mathrm { t } + 80 . How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.


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