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The Following MINITAB Output Presents A 95%95 \% Confidence Interval Find the Sample Size Needed So That The

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The following MINITAB output presents a 95%95 \% confidence interval.
 The assumed sigma =7.9655 Variable N Mean  SE Mean 95%CIx5653.5591.0644(51.473,55.645) \begin{array}{ccccc}\hline{\text { The assumed sigma }=7.9655} & \\\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \\\mathrm{x} & 56 & 53.559 & 1.0644 & (51.473,55.645) \\\hline\end{array}

Find the sample size needed so that the 99%99 \% confidence interval will have a margin of err 1.11.1 . rror of


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