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Suppose We Wish to Construct a Confidence Interval for a Population

question 35

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Suppose we wish to construct a confidence interval for a population proportion p. If we sample without replacement from a relatively small population of size N, the margin of error E is modified to include the finite population correction factor as follows: E=zα/2pq^nNnN1E = z _ { \alpha } / 2 \sqrt { \frac { \hat { p q } } { n } } \sqrt { \frac { N - n } { N - 1 } }
Construct a 90%90 \% confidence interval for the proportion of students at a school who are left handed. The number of students at the school is N=410N = 410 . In a random sample of 89 students, selected without replacement, there are 10 left handers.


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