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When Sampling Without Replacement from a Finite Population of Size σx=σnNnN1\sigma _ { x } ^ { - } = \frac { \sigma } { \sqrt { n } } \sqrt { \frac { N - n } { N - 1 } }

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When sampling without replacement from a finite population of size N, the following formula is used to find the standard deviation of the population of sample means: σx=σnNnN1\sigma _ { x } ^ { - } = \frac { \sigma } { \sqrt { n } } \sqrt { \frac { N - n } { N - 1 } } However, when the sample size n, is smaller than 5% of the population size, N, the finite population correction factor, NnN1\sqrt { \frac { N - n } { N - 1 } } , can be omitted. Explain in your own words why this is reasonable. For N=200\mathrm { N } = 200 nd the values of the finite population correction factor when the sample size is 10%, 5%, 3%, 1% of the population, respectively. What do you notice?


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