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Consider the Nuclear Reaction 7Li+1p4He+4He7 \mathrm { Li } + 1 \mathrm { p } \rightarrow 4 \mathrm { He } + 4 \mathrm { He }

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Consider the nuclear reaction: 7Li+1p4He+4He7 \mathrm { Li } + 1 \mathrm { p } \rightarrow 4 \mathrm { He } + 4 \mathrm { He } . The known atomic masses are 7 Li: 7.016005u\quad 7.016005 \mathrm { u }
24He:4.002603u{ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }
1p: 1.007825u\quad 1.007825 \mathrm { u }
What is the QQ -value (or reaction energy) of this reaction? (1u=931.5MeV/c2) \left( 1 \mathrm { u } = 931.5 \mathrm { MeV } / \mathrm { c } ^ { 2 } \right)


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