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The Radius RR Of a Nucleus of Mass Number AA Is Given By

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Short Answer

The radius RR of a nucleus of mass number AA is given by R=R0A1/3R = R _ { 0 } A ^ { 1 / 3 } , where R0=1.2×R _ { 0 } = 1.2 \times 1015 m10 ^ { - 15 } \mathrm {~m} , calculate the density of a nucleus that has contains 57 protons and 82 neutrons. The mass of a nucleon (proton or neutron) is 1.67×1027 kg1.67 \times 10 ^ { - 27 } \mathrm {~kg} .


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