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A Summary of the Nuclear Reactions That Power Our Sun 4p4He+2e4 \mathrm { p } \rightarrow 4 \mathrm { He } + 2 \mathrm { e } ^ { - }

question 44

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A summary of the nuclear reactions that power our sun is 4p4He+2e4 \mathrm { p } \rightarrow 4 \mathrm { He } + 2 \mathrm { e } ^ { - } , with masses of 938.272938.272 MeV/c2\mathrm { MeV } / \mathrm { c } ^ { 2 } for a proton, 3727.38MeV/c23727.38 \mathrm { MeV } / \mathrm { c } ^ { 2 } for the helium nucleus, and 0.511MeV/c20.511 \mathrm { MeV } / \mathrm { c } ^ { 2 } for each electron. How much energy is released by each of these reactions?


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