In a Head-On Collision, an Alpha Particle $( Z = 2 )$

question 123

Multiple Choice

In a head-on collision, an alpha particle $( Z = 2 )$ of energy $8.20 \mathrm { MeV }$ bounces straight back from a nucleus of charge $80.0 \mathrm { e }$ . How close were the centers of the objects at closest approach? $( 1 \mathrm { eV } = 1.60$ $\times 10 ^ { - 19 } \mathrm {~J} , e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , 1 / 4 \pi \varepsilon _ { 0 } = 8.99 \times 10 ^ { 9 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { C } ^ { 2 }$ )

• A) \(3.39 \times 10 ^ { - 12 } \mathrm {~m}\)
• B) \(6.56 \times 10 ^ { - 15 } \mathrm {~m}\)
• C) \(2.81 \times 10 ^ { - 14 } \mathrm {~m}\)
• D) \(2.17 \times 10 ^ { - 14 } \mathrm {~m}\)

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