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Estimate the Maximum Rotational Energy (In Electron-Volts) for a Free L=2L = 2

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Estimate the maximum rotational energy (in electron-volts) for a free and freely-spinning diatomic hydrogen molecule in the L=2L = 2 quantum state. The equilibrium separation for the atoms in the H2\mathrm { H } _ { 2 } molecule is 0.075 nm.(1eV=1.60×1019 J,mproton =1.67×1027 kg,h=6.626×10340.075 \mathrm {~nm} . \left( 1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , m _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} , h = 6.626 \times 10 ^ { - 34 } \right. J.s)


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