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The Spacing of the Atoms of a Crystal Is 159pm159 \mathrm { pm }

question 67

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The spacing of the atoms of a crystal is 159pm159 \mathrm { pm } . A monoenergetic beam of neutrons directed normally at the surface of the crystal undergoes first order diffraction at an angle of 5858 ^ { \circ } from the normal. What is the energy of each of the neutrons? ( mneutron =1.675×1027 kg,1eV=1.6×m _ { \text {neutron } } = 1.675 \times 10 ^ { - 27 } \mathrm {~kg} , 1 \mathrm { eV } = 1.6 \times 1019 J,h=6.626×1034 Js) \left. 10 ^ { - 19 } \mathrm {~J} , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)

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