The Maximum Magnetic Energy Density of a Sinusoidal Electromagnetic Wave $8.95 \times 10 ^ { - 5 } \mathrm {~J} / \mathrm { m } ^ { 3 }$

question 43

Multiple Choice

The maximum magnetic energy density of a sinusoidal electromagnetic wave is $8.95 \times 10 ^ { - 5 } \mathrm {~J} / \mathrm { m } ^ { 3 }$ . What is the amplitude of the magnetic field component of this wave? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , \mu _ { 0 } = 4 \pi \times \right.$ $10 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A } , \varepsilon _ { 0 } = 8.85 \times 10 ^ { - 12 } \mathrm { C } ^ { 2 } / \mathrm { N } \cdot \mathrm { m } ^ { 2 }$ )

• A) \(12.0 \mu \mathrm { T }\)
• B) \(13.0 \mu \mathrm { T }\)
• C) \(14.0 \mu \mathrm { T }\)
• D) \(16.0 \mu \mathrm { T }\)
• E) \(15.0 \mu \mathrm { T }\)

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