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A Proton, Starting from Rest, Accelerates Through a Potential Difference 1.0kV1.0 \mathrm { kV }

question 27

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A proton, starting from rest, accelerates through a potential difference of 1.0kV1.0 \mathrm { kV } and then moves into a magnetic field of 0.040 T0.040 \mathrm {~T} at a right angle to the field. What is the radius of the proton's resulting orbit? (e=1.60×1019C,mproton =1.67×1027 kg) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} \right)


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