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A Proton Moving with a Velocity Of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }

question 130

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A proton moving with a velocity of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s } along the +y+ y -axis enters a magnetic field of 0.20 T0.20 \mathrm {~T} directed towards the x- x -axis. What is the magnitude of the magnetic force acting on the proton? (e( e =1.60×1019C= 1.60 \times 10 ^ { - 19 } \mathrm { C } )


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