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An Electron Is Accelerated from Rest Through a Potential Difference 3.75kV3.75 \mathrm { kV }

question 9

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An electron is accelerated from rest through a potential difference of 3.75kV3.75 \mathrm { kV } . It enters a region where a uniform 4.0-mT magnetic field is perpendicular to the velocity of the electron. Calculate the radius of the path this electron will follow in the magnetic field. (e=1.60×1019C,melectron =\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {electron } } = \right. 9.11×1031 kg9.11 \times 10 ^ { - 31 } \mathrm {~kg} )


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