The Current Through A $50 - \Omega$ Resistor Is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$

question 198

Short Answer

The current through a $50 - \Omega$ resistor is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$ . What are (a) the current amplitude and (b) the rms current?

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