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The Current Through A 50Ω50 - \Omega Resistor Is I=(0.80 A)sin(240t)I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )

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The current through a 50Ω50 - \Omega resistor is I=(0.80 A) sin(240t) I = ( 0.80 \mathrm {~A} ) \sin ( 240 t ) , where tt is measured in seconds. How much power on average is dissipated in the resistor?

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