A Proton with a Speed Of $2.0 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$

question 2

Multiple Choice

A proton with a speed of $2.0 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$ accelerates through a potential difference and thereby increases its speed to $4.0 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$ . Through what magnitude potential difference did the proton accelerate? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} \right)$

• A) \(840 \mathrm {~V}\)
• B) \(1000 \mathrm {~V}\)
• C) \(100 \mathrm {~V}\)
• D) \(210 \mathrm {~V}\)
• E) \(630 \mathrm {~V}\)

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