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A Parallel-Plate Capacitor with Plate Separation Of 4.0 cm4.0 \mathrm {~cm} Has a Plate Area Of

question 102

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A parallel-plate capacitor with plate separation of 4.0 cm4.0 \mathrm {~cm} has a plate area of 6.0×102 m26.0 \times 10 ^ { - 2 } \mathrm {~m} ^ { 2 } .What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.42.4 is placed between the plates, completely filling the space? (ε0=8.85×1012C2/Nm2\left( \varepsilon _ { 0 } = 8.85 \times 10 ^ { - 12 } \mathrm { C } 2 / \mathrm { N } \cdot \mathrm { m } ^ { 2 } \right. )


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