A Proton Is Placed in an Electric Field of Intensity $800 \mathrm {~N} / \mathrm { C }$

question 69

Multiple Choice

A proton is placed in an electric field of intensity $800 \mathrm {~N} / \mathrm { C }$ . What are the magnitude and direction of the acceleration of the proton due to this field? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , \mathrm { m } _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} \right)$

• A) \(76.6 \times 10 ^ { 10 } \mathrm {~m} / \mathrm { s } ^ { 2 }\) opposite to the electric field
• B) \(7.66 \times 10 ^ { 10 } \mathrm {~m} / \mathrm { s } ^ { 2 }\) opposite to the electric field
• C) \(7.66 \times 10 ^ { 10 } \mathrm {~m} / \mathrm { s } ^ { 2 }\) in the direction of the electric field
• D) \(7.66 \times 10 ^ { 9 } \mathrm {~m} / \mathrm { s } ^ { 2 }\) opposite to the electric field
• E) \(76.6 \times 10^{10} \mathrm {~m} / \mathrm { s } ^ { 2 }\) in the direction of the electric field

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