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If 50 G of Lead (Of Specific Heat 0.11kcal/kgC)\left. 0.11 \mathrm { kcal } / \mathrm { kg } \cdot \mathrm { C } ^ { \circ } \right)

question 77

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If 50 g of lead (of specific heat 0.11kcal/kgC) \left. 0.11 \mathrm { kcal } / \mathrm { kg } \cdot \mathrm { C } ^ { \circ } \right) at 100C100 ^ { \circ } \mathrm { C } is put into 75 g of water (of specific heat 1.0kcal/kgC)  at 0C\left. 1.0 \mathrm { kcal } / \mathrm { kg } \cdot \mathrm { C } ^ { \circ } \right) \text { at } 0 ^ { \circ } \mathrm { C } What is the final temperature of the mixture?


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