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When Sampling Without Replacement from a Finite Population of Size σx=σnNnN1\sigma _ { x } ^ { - } = \frac { \sigma } { \sqrt { n } } \sqrt { \frac { N - n } { N - 1 } }

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When sampling without replacement from a finite population of size N, the following formula is used to find the standard deviation of the population of sample means: σx=σnNnN1\sigma _ { x } ^ { - } = \frac { \sigma } { \sqrt { n } } \sqrt { \frac { N - n } { N - 1 } }
However, when the sample size n\mathrm { n } , is smaller than 5%5 \% of the population size, N\mathrm { N } , the finite population correction f\mathrm { f } , NnN1\sqrt { \frac { \mathrm { N } - \mathrm { n } } { \mathrm { N } - 1 } } , can be omitted. Explain in your own words why this is reasonable. For N=200\mathrm { N } = 200 , find the values of the finite population correction factor when the sample size is 10%,5%,3%,1%10 \% , 5 \% , 3 \% , 1 \% of the population, respectively. What do you notice?

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