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Solve the Problem h=dcotAcotBft\mathrm { h } = \frac { \mathrm { d } } { \cot \mathrm { A } - \cot \mathrm { B } } \mathrm { ft } \text {. }

question 97

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Solve the problem.
-It can be shown that if the angle of elevation from an observer to the top of an object is A and the angle of elevation d ft closer is B, then the height of the object is given by h=dcotAcotBft\mathrm { h } = \frac { \mathrm { d } } { \cot \mathrm { A } - \cot \mathrm { B } } \mathrm { ft } \text {. }
Find A\mathrm { A } if h=50ft,d=20ft\mathrm { h } = 50 \mathrm { ft } , \mathrm { d } = 20 \mathrm { ft } , and B=61\mathrm { B } = 61 ^ { \circ } . Give your answer in degrees to the nearest hundredth.


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