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Solve the Equation in the Interval [0°, 360°) 2cos2θ+7sinθ=52 \cos 2 \theta + 7 \sin \theta = 5

question 139

Multiple Choice

Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- 2cos2θ+7sinθ=52 \cos 2 \theta + 7 \sin \theta = 5


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