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Solve the Equation for Exact Solutions Over the Interval [0 [0,2π)[ 0,2 \pi )

question 114

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Solve the equation for exact solutions over the interval [0, 2 [0,2π) [ 0,2 \pi )
- sin2xcos2x=0\sin ^ { 2 } x - \cos ^ { 2 } x = 0


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