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Solve the Equation in the Interval [0°, 360°) sin2θsinθ12=0\sin ^ { 2 } \theta - \sin \theta - 12 = 0

question 136

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Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- sin2θsinθ12=0\sin ^ { 2 } \theta - \sin \theta - 12 = 0


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