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Solve the Problem dft\mathrm { d } \mathrm { ft }

question 28

Multiple Choice

Solve the problem.
-It can be shown that if the angle of elevation from an observer to the top of an object is A and the angle of elevation dft\mathrm { d } \mathrm { ft } closer is B\mathrm { B } , then the distance from the object to the closest point of observation is given by
D=dcotBcotAcotBft\mathrm { D } = \frac { \mathrm { d } \cot \mathrm { B } } { \cot \mathrm { A } - \cot \mathrm { B } } \mathrm { ft } \text {. }
Find BB if D=20ft,d=30ftD = 20 \mathrm { ft } , \mathrm { d } = 30 \mathrm { ft } , and A=51A = 51 ^ { \circ } . Give your answer in degrees to the nearest hundredth.


Definitions:

Premium on Bonds

The amount by which the selling or market price of a bond exceeds its face value or par value.

Face Value

The nominal value printed on a financial instrument like a bond or stock certificate, representing its value at issuance.

Retirement

The act of leaving one's job and ceasing to work, typically due to age or other personal reasons, often involving the receipt of a pension or other retirement benefits.

Carrying Value

The book value of an asset on a company's balance sheet, equal to its cost minus accumulated depreciation or amortization.

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