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Solve the Equation for Solutions in the Interval [0, 2 [0,2π).[ 0,2 \pi ) .

question 131

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Solve the equation for solutions in the interval [0, 2 [0,2π) .[ 0,2 \pi ) .
- 2cos2x=1\sqrt { 2 } \cos 2 x = 1


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