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Solve the Equation for Solutions in the Interval [0°, 360°) cos2θ2=1\cos ^ { 2 } \frac { \theta } { 2 } = 1

question 13

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Solve the equation for solutions in the interval [0°, 360°) . Round to the nearest degree.
- cos2θ2=1\cos ^ { 2 } \frac { \theta } { 2 } = 1


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