Solve the Equation for Exact Solutions $$( \sec \alpha + \tan \alpha ) ^ { 2 } = \frac { 1 + \sin \alpha } { 1 - \sin \alpha }$$

question 58

Essay

Solve the equation for exact solutions.
- $$( \sec \alpha + \tan \alpha ) ^ { 2 } = \frac { 1 + \sin \alpha } { 1 - \sin \alpha }$$

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